FILL THE GAP GAME PLAY STORE ANDROID
This how-to was created using a Pixel 6 running Android 12, but your interface may be slightly different, depending on the model of your phone and which Android version you’re running. If you’re new to Android, this may help you stay organized from day one if you’re an experienced user, you might pick up a few tips.Īs you go through these suggestions, keep in mind that not all Android interfaces are the same. There are essentially two steps to making sense of all of those Android apps: find a way to organize them (and there are a variety of ways, depending on what you’re comfortable with) and periodically remove all of the extra apps that you’ve accumulated and no longer use. (Here, we can take as written the obligatory KonMari reference.) And if you’re really an app enthusiast, it can start taking up more space than you can spare. In a very short time, it can become a mess. Then, a few months later, as you’re scrolling through your app drawer, you’re surprised to see several apps that you forgot about and perhaps don’t even remember what they’re used for. If you’re anything like me, you’re constantly adding new apps, deciding they’re okay but not great, adding another, and so on. F(i, j) represents the maximum value the userį(i, j) = Max(Vi + min(F(i+2, j), F(i+1, j-1) ),Īs user wants to maximise the number of coins.If you’ve had an Android phone for any length of time, it’s easy to get used to living with, well, chaos. the user can collect the value Vj + min(F(i+1, j-1), F(i, j-2) ) where is the range of array indices available for the user if the opponent picks jth coin and is the range of indices available to the user if the opponent picks up the ith coin.įollowing is the recursive solution that is based on the above two choices. The opponent intends to choose the coin which leaves the user with minimum value, i.e. The user chooses the ‘jth’ coin with value ‘Vj’: The opponent either chooses ‘ith’ coin or ‘(j-1)th’ coin.The user can collect the value Vi + min(F(i+2, j), F(i+1, j-1) ) where is the range of array indices available to the user if the opponent chooses Vi+1 and is the range of array indexes available if opponent chooses the jth coin. The opponent intends to choose the coin which leaves the user with minimum value. The user chooses the ‘ith’ coin with value ‘Vi’: The opponent either chooses (i+1)th coin or jth coin.Now let’s see how the opponent can achieve this. Recommended PracticeOptimal Strategy For A GameTry It!Īpproach: As both the players are equally strong, both will try to reduce the possibility of winning of each other. Rearrange array such that arr >= arr if i is even and arrWrite a program to reverse an array or string.Write a program to reverse digits of a number.
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Reverse digits of an integer with overflow handled.
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Maximum and minimum of an array using minimum number of comparisons.Find the smallest and second smallest elements in an array.Find Second largest element in an array.k-th smallest absolute difference of two elements in an array.Find k pairs with smallest sums in two arrays.k smallest elements in same order using O(1) extra space.
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